What are the solutions to the equation 16+4x^2=0 ?

The solutions to the equation 16+4x^2=0 are x=2i,x=-2i

Find the zeros of 16+4x^2=0

The zeros of 16+4x^2=0 are x=2i,x=-2i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16 + 4 x^{2} = 0

x = 2 i, x = - 2 i

Solution steps

16 + 4 x^{2} = 0

Move

16

to the right side

4 x^{2} = - 16

Divide both sides by

4

x^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4, x = - - 4

- 4 = 2 i

- - 4 = - 2 i

x = 2 i, x = - 2 i

m^{2} + 6 m - 16 = 0

2 (- 3)

3 x^{2} - 2 x - 1 > 0

w^{4} - 16

\frac{1}{6} (a + 8) = \frac{3 - 2 a}{4} + 2 a - \frac{73}{12}

What are the solutions to the equation 16+4x^2=0 ?
The solutions to the equation 16+4x^2=0 are x=2i,x=-2i
Find the zeros of 16+4x^2=0
The zeros of 16+4x^2=0 are x=2i,x=-2i