x^2-5x-6>0

Lösung

x^{2} - 5 x - 6 > 0

x < - 1 or x > 6

Intervall-Notation

(- \infty, - 1) \cup (6, \infty)

Schritte zur Lösung

x^{2} - 5 x - 6 > 0

Faktorisiere

x^{2} - 5 x - 6 : (x + 1) (x - 6)

(x + 1) (x - 6) > 0

Identifiziere die Intervalle

x < - 1 or x > 6

2 x^{2} + 7 x + 6 = 0

w (w + 6) = 91

2 (3 y + 8) = 40

f a c t or 169 m^{2} - 4 u^{2}

- 3 (x + 2) \leq 5 x + 9