3r^2+6r+3=0

解答

3 r^{2} + 6 r + 3 = 0

r = - 1

求解步骤

3 r^{2} + 6 r + 3 = 0

使用求根公式求解

r_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

6^{2} - 4 \cdot 3 \cdot 3 = 0

r_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 3}

r = \frac{- 6}{2 \cdot 3}

\frac{- 6}{2 \cdot 3} = - 1

r = - 1

二次方程组的解是:

r = - 1

∣ x - 3 ∣ + ∣ x - 4 ∣ = 9

4 x + 3 = 10 + 4 x + 7 (3 + 2 x)

s im pl i f y \frac{- 5 x ^{2} y ^{3} z ^{4}}{15 x ^{4} y ^{2} z ^{4}}

7 x^{2} + 44 x + 45 = 0

s im pl i f y \frac{- \frac{1}{8}}{\frac{5}{24}}