(3x+1)/(x-4)<= 0

解答

\frac{3 x + 1}{x - 4} \leq 0

- \frac{1}{3} \leq x < 4

间隔符号

[- \frac{1}{3}, 4)

十进制

- 0.33333 \dots \leq x < 4

求解步骤

\frac{3 x + 1}{x - 4} \leq 0

确定区间

- \frac{1}{3} \leq x < 4

s im pl i f y \frac{\frac{4}{3}}{2}

∣ x + 4 ∣ \geq 8

\frac{3}{4} x + 2 \leq \frac{1}{4} x + 5

s im pl i f y (2 x^{3} y^{2} z^{2})^{3} (x^{2} z)^{4}

f a c t or 9 a^{2} + 24 ab + 16 b^{2}