-10q^2+2600q-150000=0

解

- 10 q^{2} + 2600 q - 150000 = 0

q = 10 (13 - 19), q = 10 (13 + 19)

十進法表記

q = 86.41101 \dots, q = 173.58898 \dots

解答ステップ

- 10 q^{2} + 2600 q - 150000 = 0

解くとthe二次式

q_{1, 2} = \frac{- 2600 \pm 260 0 ^{2} - 4 ( - 10 ) ( - 150000 )}{2 ( - 10 )}

260 0^{2} - 4 (- 10) (- 150000) = 20019

q_{1, 2} = \frac{- 2600 \pm 200 19}{2 ( - 10 )}

解を分離する

q_{1} = \frac{- 2600 + 200 19}{2 ( - 10 )}, q_{2} = \frac{- 2600 - 200 19}{2 ( - 10 )}

q = \frac{- 2600 + 200 19}{2 ( - 10 )} : 10 (13 - 19)

q = \frac{- 2600 - 200 19}{2 ( - 10 )} : 10 (13 + 19)

二次equationの解:

q = 10 (13 - 19), q = 10 (13 + 19)