faktorisieren 3x^4+6x^3-3x^2-6x

Lösung

faktorisieren

3 x^{4} + 6 x^{3} - 3 x^{2} - 6 x

3 x (x + 2) (x + 1) (x - 1)

Schritte zur Lösung

3 x^{4} + 6 x^{3} - 3 x^{2} - 6 x

Klammere gleiche Terme aus

3 x : 3 x (x^{3} + 2 x^{2} - x - 2)

= 3 x (x^{3} + 2 x^{2} - x - 2)

Faktorisiere

x^{3} + 2 x^{2} - x - 2 : (x + 2) (x + 1) (x - 1)

= 3 x (x + 2) (x + 1) (x - 1)

\frac{1}{2} (x + \frac{1}{3}) = \frac{5}{3}

4 x^{2} - 5 x + 1 = 0

4 x^{2} \leq 1

3 a^{2} = 6 a - 3

lo g_{9} (3) = w