4v^2-28v=0

解

4 v^{2} - 28 v = 0

v = 7, v = 0

解答ステップ

4 v^{2} - 28 v = 0

解くとthe二次式

v_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 28)^{2} - 4 \cdot 4 \cdot 0 = 28

v_{1, 2} = \frac{- ( - 28 ) \pm 28}{2 \cdot 4}

解を分離する

v_{1} = \frac{- ( - 28 ) + 28}{2 \cdot 4}, v_{2} = \frac{- ( - 28 ) - 28}{2 \cdot 4}

v = \frac{- ( - 28 ) + 28}{2 \cdot 4} : 7

v = \frac{- ( - 28 ) - 28}{2 \cdot 4} : 0

二次equationの解:

v = 7, v = 0