simplificar (14a^4b^6c^{-10})/(8a^{-2)b^3c^{-5}}

Solução

simplificar

\frac{14 a ^{4} b ^{6} c ^{- 10}}{8 a ^{- 2} b ^{3} c ^{- 5}}

\frac{7 a ^{6} b ^{3}}{4 c ^{5}}

Passos da solução

\frac{14 a ^{4} b ^{6} c ^{- 10}}{8 a ^{- 2} b ^{3} c ^{- 5}}

Fatorar o número:

14 = 2 \cdot 7

= \frac{2 \cdot 7 a ^{4} b ^{6} c ^{- 10}}{8 a ^{- 2} b ^{3} c ^{- 5}}

Fatorar o número:

8 = 2 \cdot 4

= \frac{2 \cdot 7 a ^{4} b ^{6} c ^{- 10}}{2 \cdot 4 a ^{- 2} b ^{3} c ^{- 5}}

Eliminar o fator comum:

2

= \frac{7 a ^{4} b ^{6} c ^{- 10}}{4 a ^{- 2} b ^{3} c ^{- 5}}

Simplificar

\frac{a ^{4}}{a ^{- 2}} : a^{6}

= \frac{7 a ^{6} b ^{6} c ^{- 10}}{4 b ^{3} c ^{- 5}}

Simplificar

\frac{b ^{6}}{b ^{3}} : b^{3}

= \frac{7 a ^{6} b ^{3} c ^{- 10}}{4 c ^{- 5}}

Simplificar

\frac{c ^{- 10}}{c ^{- 5}} : \frac{1}{c ^{5}}

= \frac{7 a ^{6} b ^{3}}{4 c ^{5}}

f a c t or p^{2} + 7 pq - 18 q^{2}

7 x - 1 > 3 x + 7

- 8 \geq 1.6 m

f a c t or 9 y^{2} - (2 x - y)^{2}

- 16 t^{2} + 44 t + 28 = 0