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Frequently Asked Questions (FAQ)
What are the solutions to the equation 5x^2+1=4x-7 ?
- The solutions to the equation 5x^2+1=4x-7 are x= 2/5+i 6/5 ,x= 2/5-i 6/5
Find the zeros of 5x^2+1=4x-7
- The zeros of 5x^2+1=4x-7 are x= 2/5+i 6/5 ,x= 2/5-i 6/5