What are the solutions to the equation completesquare x^2-4x-8=0 ?

The solutions to the equation completesquare x^2-4x-8=0 are x=2sqrt(3)+2,x=-2sqrt(3)+2

Find the zeros of completesquare x^2-4x-8=0

The zeros of completesquare x^2-4x-8=0 are x=2sqrt(3)+2,x=-2sqrt(3)+2

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x^{2} - 4 x - 8 = 0

x = 23 + 2, x = - 23 + 2

Solution steps

x^{2} - 4 x - 8 = 0

Move

8

to the right side

x^{2} - 4 x = 8

Rewrite in the form

(x + a)^{2} = b

(x - 2)^{2} = 12

For

the solutions are

f (x) = a, - a

Solve

x - 2 = 12 : x = 23 + 2

Solve

x - 2 = - 12 : x = - 23 + 2

The solutions to the quadratic equation are:

x = 23 + 2, x = - 23 + 2

\frac{140}{700}

x, 4 x + 4 \leq 9 x + 8

x, 3 = 2 (x) - 10

- 184/8

t, i = Pt

What are the solutions to the equation completesquare x^2-4x-8=0 ?
The solutions to the equation completesquare x^2-4x-8=0 are x=2sqrt(3)+2,x=-2sqrt(3)+2
Find the zeros of completesquare x^2-4x-8=0
The zeros of completesquare x^2-4x-8=0 are x=2sqrt(3)+2,x=-2sqrt(3)+2