What are the solutions to the equation quadraticformula 3x^2-2x=9 ?

The solutions to the equation quadraticformula 3x^2-2x=9 are x=(1+2sqrt(7))/3 ,x=(1-2sqrt(7))/3

Find the zeros of quadraticformula 3x^2-2x=9

The zeros of quadraticformula 3x^2-2x=9 are x=(1+2sqrt(7))/3 ,x=(1-2sqrt(7))/3

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3 x^{2} - 2 x = 9

x = \frac{1 + 2 7}{3}, x = \frac{1 - 2 7}{3}

Solution steps

3 x^{2} - 2 x = 9

Move

9

to the left side

3 x^{2} - 2 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 9) = 47

x_{1, 2} = \frac{- ( - 2 ) \pm 4 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 7}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 4 7}{2 \cdot 3}

x = \frac{- ( - 2 ) + 4 7}{2 \cdot 3} : \frac{1 + 2 7}{3}

x = \frac{- ( - 2 ) - 4 7}{2 \cdot 3} : \frac{1 - 2 7}{3}

The solutions to the quadratic equation are:

x = \frac{1 + 2 7}{3}, x = \frac{1 - 2 7}{3}

\frac{12}{5}

- 5.8 + 4.2 - 3.1 + 1.4 c

36/18

\frac{1}{2} \cdot (x - 3)

m, m x = y

What are the solutions to the equation quadraticformula 3x^2-2x=9 ?
The solutions to the equation quadraticformula 3x^2-2x=9 are x=(1+2sqrt(7))/3 ,x=(1-2sqrt(7))/3
Find the zeros of quadraticformula 3x^2-2x=9
The zeros of quadraticformula 3x^2-2x=9 are x=(1+2sqrt(7))/3 ,x=(1-2sqrt(7))/3