x=3+t,y=-t^2

Lösung

x = 3 + t, y = - t^{2}

3 - t^{2}

Schritte zur Lösung

Finde

x \circ y

gegeben

x = 3 + t, y = - t^{2}

x \circ y = (x) ((y) (t))

y = - t^{2}

= (x) (- t^{2})

(x) (- t^{2}) : 3 - t^{2}

= 3 - t^{2}

so l v e f or x, 3 x < 12

so l v e f or a, 2 = - a

40/20

f a c t or 4 x^{2} - 5

so l v e f or x, 4 x = 3