2^{2x-7}=16

Lösung

2^{2 x - 7} = 16

x = \frac{11}{2}

Dezimale

x = 5.5

Schritte zur Lösung

2^{2 x - 7} = 16

Wende Exponentenregel an

2 x - 7 = 4

Löse

2 x - 7 = 4 : x = \frac{11}{2}

x = \frac{11}{2}

2 = (1.07)^{x}

6^{2 x + 1} = 216

12 5^{3 x + 7} = 2 5^{5 x - 11}

3^{2 x} = \frac{1}{9}

2 \cdot 3^{x} + 5 \cdot 3^{x} - 3^{x} = 6