25^x= 1/(sqrt(5))

Lösung

2 5^{x} = \frac{1}{5}

x = - \frac{1}{4}

Dezimale

x = - 0.25

Schritte zur Lösung

2 5^{x} = \frac{1}{5}

Wende Exponentenregel an

2 x = - \frac{1}{2}

Löse

2 x = - \frac{1}{2} : x = - \frac{1}{4}

x = - \frac{1}{4}

1 6^{x} - 17 \times 4^{x} + 16 = 0

2 (1 0^{3 x}) - 3 = 15

7 \cdot 2^{x} = 1

1 0^{x - 2} = 1

8^{x + 2} = 16