11^{3x-2}=65

解答

1 1^{3 x - 2} = 65

x = \frac{ln ( 7865 )}{3 ln ( 11 )}

十进制

x = 1.24695 \dots

求解步骤

1 1^{3 x - 2} = 65

使用指数运算法则

(3 x - 2) ln (11) = ln (65)

解

(3 x - 2) ln (11) = ln (65) : x = \frac{ln ( 7865 )}{3 ln ( 11 )}

x = \frac{ln ( 7865 )}{3 ln ( 11 )}

3^{x} - 3^{x - 1} - 7 \cdot 3^{x - 3} = 33

3 e^{- x} x^{2} - e^{- x} x^{3} = 0

8^{x + 3} = \frac{1}{16}

3^{2 x - 1} = 2^{x + 3}

2^{x - 4} = 4^{x + 5}