8^{4x+1}=1

Lösung

8^{4 x + 1} = 1

x = - \frac{1}{4}

Dezimale

x = - 0.25

Schritte zur Lösung

8^{4 x + 1} = 1

Wende Exponentenregel an

(4 x + 1) ln (8) = ln (1)

Löse

(4 x + 1) ln (8) = ln (1) : x = - \frac{1}{4}

x = - \frac{1}{4}

2 e^{6 x} = 13

2^{2 x} - 4^{x - 1} = 12

x^{2} = 1 6^{x}

0.2 5^{2 x - 1} = 8^{x + 3}

e^{x^{2} - 3} = e^{x - 2}