1/(y-2)=(2y+1)/(y^2-4)

解答

\frac{1}{y - 2} = \frac{2 y + 1}{y ^{2} - 4}

y = 1

求解步骤

\frac{1}{y - 2} = \frac{2 y + 1}{y ^{2} - 4}

使用分式交叉相乘

y^{2} - 4 = (y - 2) (2 y + 1)

解

y^{2} - 4 = (y - 2) (2 y + 1) : y = 2, y = 1

y = 2, y = 1

验证解

找到无定义的点（奇点）:

y = 2, y = - 2

因为方程对以下值无定义:

2

y = 1

\frac{15 - 2 x - x ^{2}}{x - 4} = 0

\frac{3 z - 6}{7 - 2 z} = \frac{1.2}{3.2}

\frac{8}{x ^{2}} + 1 = \frac{9}{x}

\frac{1}{x + 9} - 1 = \frac{x}{x + 9}

\frac{1}{2 x} + \frac{3}{x + 7} = \frac{- 1}{x}