solvefor x,3x^2-2+2sinx=0

解

解く

x, 3 x^{2} - 2 + 2 sin (x) = 0

x \approx - 1.1263

度

x = - 64.53223 \dots^{\circ}

解答ステップ

3 x^{2} - 2 + 2 sin (x) = 0

Find the interval where both equation sides share the same range:

- \frac{2}{3} \leq x \leq \frac{2}{3}

- \frac{2}{3} \leq x \leq \frac{2}{3}

Find the difference function:

3 x^{2} + 2 sin (x) - 2

3 x^{2} + 2 sin (x) - 2

Extreme points of

3 x^{2} + 2 sin (x) - 2

- \frac{2}{3} \leq x \leq \frac{2}{3}

(- \frac{2}{3}, - 2 sin (\frac{2}{3}) + 2), (- 0.31675, - 2.32196 \dots), (\frac{2}{3}, 2 sin (\frac{2}{3}) + 2)

Find the x-axis intersections

x \approx - 1.1263, x \approx 0.55937

equationは以下で未定義のため:

0.55937

x \approx - 1.1263