solvefor x,-7sinx+3x^2=-1/3

解

解く

x, - 7 sin (x) + 3 x^{2} = - \frac{1}{3}

x \approx 1.48803

度

x = 85.25783 \dots^{\circ}

解答ステップ

- 7 sin (x) + 3 x^{2} = - \frac{1}{3}

Find the interval where both equation sides share the same range:

- \frac{2 5}{3} \leq x \leq \frac{2 5}{3}

- \frac{2 5}{3} \leq x \leq \frac{2 5}{3}

Find the difference function:

- 7 sin (x) + 3 x^{2} + \frac{1}{3}

- 7 sin (x) + 3 x^{2} + \frac{1}{3}

Extreme points of

- 7 sin (x) + 3 x^{2} + \frac{1}{3}

- \frac{2 5}{3} \leq x \leq \frac{2 5}{3}

(- \frac{2 5}{3}, 7 sin (\frac{2 5}{3}) + 7), (0.80697, - 2.76842 \dots), (\frac{2 5}{3}, - 7 sin (\frac{2 5}{3}) + 7)

Find the x-axis intersections

x \approx 0.04865, x \approx 1.48803

equationは以下で未定義のため:

0.04865

x \approx 1.48803