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受欢迎的代数 >

10b^2+21b+6=2b

解答

10 b^{2} + 21 b + 6 = 2 b

解答

b = - \frac{2}{5}, b = - \frac{3}{2}

+1

十进制

b = - 0.4, b = - 1.5

求解步骤

10 b^{2} + 21 b + 6 = 2 b

将

2 b

para o lado esquerdo

10 b^{2} + 19 b + 6 = 0

使用求根公式求解

b_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 10 \cdot 6}{2 \cdot 10}

1 9^{2} - 4 \cdot 10 \cdot 6 = 11

b_{1, 2} = \frac{- 19 \pm 11}{2 \cdot 10}

将解分隔开

b_{1} = \frac{- 19 + 11}{2 \cdot 10}, b_{2} = \frac{- 19 - 11}{2 \cdot 10}

b = \frac{- 19 + 11}{2 \cdot 10} : - \frac{2}{5}

b = \frac{- 19 - 11}{2 \cdot 10} : - \frac{3}{2}

二次方程组的解是:

b = - \frac{2}{5}, b = - \frac{3}{2}

作图

流行的例子

(3x-7)(5x-12)=0

(3 x - 7) (5 x - 12) = 0

因式分解 16x^2=81

f a c t or 16 x^{2} = 81

-(n+2)=15(n+7)n

- (n + 2) = 15 (n + 7) n

4 x^{2} + 7 = 7 + 24 x

4(x+2)^2-46=-18

4 (x + 2)^{2} - 46 = - 18