a+bi=(a-bi)^2

解

a + bi = (a - bi)^{2}

a = 1, a = 0, a = - \frac{1}{2}, a = - \frac{1}{2}, b = 0 b = 0 b = \frac{3}{2} b = - \frac{3}{2}

解答ステップ

a + bi = (a - bi)^{2}

拡張

(a - bi)^{2} : (a^{2} - b^{2}) - 2 iab

a + bi = (a^{2} - b^{2}) - 2 iab

複素数は, その実数部と虚数部が等しい場合にのみ等しくなるequation系として書き換える:

[a = a^{2} - b^{2} b = - 2 ab]

[a = a^{2} - b^{2} b = - 2 ab] : a = 1, a = 0, a = - \frac{1}{2}, a = - \frac{1}{2}, b = 0 b = 0 b = \frac{3}{2} b = - \frac{3}{2}

a = 1, a = 0, a = - \frac{1}{2}, a = - \frac{1}{2}, b = 0 b = 0 b = \frac{3}{2} b = - \frac{3}{2}