xin^0=3y^2+x-1

解答

x i n^{0} = 3 y^{2} + x - 1

(x = 0, x = 0, y = \frac{1}{3} y = - \frac{1}{3})

求解步骤

x i n^{0} = 3 y^{2} + x - 1

将

x i n^{0}

改写成标准复数形式:

0 + x i

0 + x i = 3 y^{2} + x - 1

将

3 y^{2} + x - 1

改写成标准复数形式:

(3 y^{2} + x - 1) + 0 i

0 + x i = (3 y^{2} + x - 1) + 0 i

复数仅在实部和虚部均相等时才相等改写为方程组:

[0 = 3 y^{2} + x - 1 x = 0]

[0 = 3 y^{2} + x - 1 x = 0] : (x = 0, x = 0, y = \frac{1}{3} y = - \frac{1}{3})

(x = 0, x = 0, y = \frac{1}{3} y = - \frac{1}{3})

(x + i y)^{2} = 3 - 2 i

z^{2} - 2 z + 9 + 6 i = 0

(- 3 + 2 i)^{2} = (x + y i)^{2}

m = (i^{2})^{2^{5^{6}}}

a = (a x - B x) (ai - B i) + (- a y) (- aj)