x+2+3yi=-4x+(y+4)i

解答

x + 2 + 3 y i = - 4 x + (y + 4) i

x = - \frac{2}{5}, y = 2

求解步骤

x + 2 + 3 y i = - 4 x + (y + 4) i

复数仅在实部和虚部均相等时才相等改写为方程组:

[x + 2 = - 4 x 3 y = y + 4]

[x + 2 = - 4 x 3 y = y + 4] : x = - \frac{2}{5}, y = 2

x = - \frac{2}{5}, y = 2

(2 + i) x - y = 0

i z^{2} + 2 z = z + i

(x^{2} - 9) + (2 y - 5) i = 7 i

x + 3 i + 3 = 5 + y i

z^{2} + (1 - i) \cdot z - i = 0