2=log_{10}(2^8 1/x)

Lösung

2 = lo g_{10} (2^{8} \frac{1}{x})

x = \frac{64}{25}

Dezimale

x = 2.56

Schritte zur Lösung

2 = lo g_{10} (2^{8} \cdot \frac{1}{x})

Wende die log Regel an

100 = \frac{256}{x}

Löse

100 = \frac{256}{x} : x = \frac{64}{25}

x = \frac{64}{25}

6 (ln (2 x) + 1) = 0

lo g_{x} (8) = \frac{3}{2}

ln (x) = - a

0 = ln (x) - \frac{1}{2} x + 1

3 ln (x) - 1 = 0