2=log_{10}(3x)

Lösung

2 = lo g_{10} (3 x)

x = \frac{100}{3}

Dezimale

x = 33.33333 \dots

Schritte zur Lösung

2 = lo g_{10} (3 x)

Wende die log Regel an

100 = 3 x

Löse

100 = 3 x : x = \frac{100}{3}

x = \frac{100}{3}

lo g_{4} (lo g_{2} (x + 1)) = 1

so l v e f or x, (f x) = 2 x + ln (x)

3 ln (x - 1) = 0

8.3 = - lo g_{10} (x)

2 lo g_{5} (x) = 1