log_{3}(8-2x)=2

Lösung

lo g_{3} (8 - 2 x) = 2

x = - \frac{1}{2}

Dezimale

x = - 0.5

Schritte zur Lösung

lo g_{3} (8 - 2 x) = 2

Wende die log Regel an

8 - 2 x = 9

Löse

8 - 2 x = 9 : x = - \frac{1}{2}

x = - \frac{1}{2}

10.99 = - lo g_{10} (k)

lo g_{2} (5 \cdot x) = 3

ln (ln^{2} (\frac{x}{e})) = 0

ln (y) = \frac{11}{5}

so l v e f or x, 2 lo g_{3} (3 x - 7) + 1 = 9