log_{2}((x+1)(x-1))=3

Lösung

lo g_{2} ((x + 1) (x - 1)) = 3

x = 3, x = - 3

Schritte zur Lösung

lo g_{2} ((x + 1) (x - 1)) = 3

Wende die log Regel an

(x + 1) (x - 1) = 8

Löse

(x + 1) (x - 1) = 8 : x = 3, x = - 3

x = 3, x = - 3

lo g_{x} (3) = - \frac{1}{2}

0.4 = lo g_{10} (y)

lo g_{4} (x) - lo g_{4} (2 x - 1) = 1

lo g_{2} (8 x + 5) = 5

6 + 7 \cdot lo g_{2} (x) = 21