log_{7}(3x)=A

Lösung

lo g_{7} (3 x) = A

x = \frac{7 ^{A}}{3}

Schritte zur Lösung

lo g_{7} (3 x) = A

Wende die log Regel an

3 x = 7^{A}

Löse

3 x = 7^{A} : x = \frac{7 ^{A}}{3}

x = \frac{7 ^{A}}{3}

ln (x + 8) + ln (x - 4) = 2 ln (x)

(ln (x))^{2} - 1 = 0

lo g_{x} (\frac{25}{9}) = 2

ln (2 - x) = 3

ln (x) = ln (5)