log_{10}(x^2-16x+1)=0

Lösung

lo g_{10} (x^{2} - 16 x + 1) = 0

x = 16, x = 0

Schritte zur Lösung

lo g_{10} (x^{2} - 16 x + 1) = 0

Wende die log Regel an

x^{2} - 16 x + 1 = 1

Löse

x^{2} - 16 x + 1 = 1 : x = 16, x = 0

x = 16, x = 0

2 ln (3 x^{2} + 1) = 13

ln (15 - 2 x) = 2 ln (x)

1 = 3 lo g_{10} (4 x + 10)

lo g_{6} (9 x) - 2 lo g_{6} (2) = 3

lo g_{7} (2 x - 3) = 2