log_{3}((r+7)^2)=4

Lösung

lo g_{3} ((r + 7)^{2}) = 4

r = 2, r = - 16

Schritte zur Lösung

lo g_{3} ((r + 7)^{2}) = 4

Wende die log Regel an

(r + 7)^{2} = 81

Löse

(r + 7)^{2} = 81 : r = 2, r = - 16

r = 2, r = - 16

- 10 ln (2 p) = 40

10 lo g_{10} (x^{2}) = - 10

ln (x - 1) + ln (x) = 1

ln (C) = 0

ln (x) = ln (x + 6) - ln (2)