ln(5-2x)=-5

Lösung

ln (5 - 2 x) = - 5

x = \frac{- 1 + 5 e ^{5}}{2 e ^{5}}

Dezimale

x = 2.49663 \dots

Schritte zur Lösung

ln (5 - 2 x) = - 5

Wende die log Regel an

5 - 2 x = \frac{1}{e ^{5}}

Löse

5 - 2 x = \frac{1}{e ^{5}} : x = \frac{- 1 + 5 e ^{5}}{2 e ^{5}}

x = \frac{- 1 + 5 e ^{5}}{2 e ^{5}}

\frac{1}{x} = e^{l n (x)}

10 = \frac{50}{ln ( q + 1 )}

lo g_{10} (x) + 3 = 5

lo g_{2} (4 \cdot x) = 10

lo g_{6} (2 x - 1) = 3