log_{10}(p^{-1})=1

解答

lo g_{10} (p^{- 1}) = 1

p = \frac{1}{10}

十进制

p = 0.1

求解步骤

lo g_{10} (p^{- 1}) = 1

使用对数运算法则

\frac{1}{p} = 10

解

\frac{1}{p} = 10 : p = \frac{1}{10}

p = \frac{1}{10}

lo g_{3} (x) + 3 = 2

lo g_{10} (X) = 3.4146

so l v e f or a, a^{b} = e^{b l n (a)}

ln (x) = 7.352205355

lo g_{2} (x) = 3 - lo g_{2} (3 x - 10)