log_{e}(2x)=1

Lösung

lo g_{e} (2 x) = 1

x = \frac{e}{2}

Dezimale

x = 1.35914 \dots

Schritte zur Lösung

lo g_{e} (2 x) = 1

Wende die log Regel an

2 x = e

Löse

2 x = e : x = \frac{e}{2}

x = \frac{e}{2}

lo g_{e} (2 x) = 2

lo g_{x + 2} (3 x^{2} - 12) = 2

75 = 10 lo g_{10} (x) + 120

lo g_{1} (x) = 4

lo g_{2} (6 x) + lo g_{2} (3) = 0