log_{16}(5x-2)= 3/4

Lösung

lo g_{16} (5 x - 2) = \frac{3}{4}

x = 2

Schritte zur Lösung

lo g_{16} (5 x - 2) = \frac{3}{4}

Wende die log Regel an

5 x - 2 = 8

Löse

5 x - 2 = 8 : x = 2

x = 2

so l v e f or x, 0 = ln (x)

2 ln (3 x) = 8

lo g_{10} (3 x) + lo g_{10} (9 x) = 1

so l v e f or y, ln (y - 38) = 5 t

lo g_{16} (x + 1) = \frac{1}{2}