log_{2}(mx)=c

Lösung

lo g_{2} (m x) = c

x = \frac{2 ^{c}}{m}

Schritte zur Lösung

lo g_{2} (m x) = c

Wende die log Regel an

m x = 2^{c}

Löse

m x = 2^{c} : x = \frac{2 ^{c}}{m}

x = \frac{2 ^{c}}{m}

lo g_{10} (\frac{2 x - 4}{5}) = 2

lo g_{11} (2 x + 6) = lo g_{11} (- x)

5 lo g_{10} (2 x) = 20

ln ((x - 1)^{2}) = 8

lo g_{9} (x) = 0.25