ln(3x+1)=7.492

Lösung

ln (3 x + 1) = 7.492

x = \frac{e ^{7.492} - 1}{3}

Dezimale

x = 597.54525 \dots

Schritte zur Lösung

ln (3 x + 1) = 7.492

Wende die log Regel an

3 x + 1 = e^{7.492}

Löse

3 x + 1 = e^{7.492} : x = \frac{e ^{7.492} - 1}{3}

x = \frac{e ^{7.492} - 1}{3}

- lo g_{10} (x) = 1.3

ln (x) - ln (2 x - 5) = ln (3)

lo g_{2} ((r + 6)^{2}) = 4

so l v e f or y, 2 ln (x) = ln (y)

lo g_{x} (3) = 3