log_{3}(5x+1)=2

Lösung

lo g_{3} (5 x + 1) = 2

x = \frac{8}{5}

Dezimale

x = 1.6

Schritte zur Lösung

lo g_{3} (5 x + 1) = 2

Wende die log Regel an

5 x + 1 = 9

Löse

5 x + 1 = 9 : x = \frac{8}{5}

x = \frac{8}{5}

- 8 + lo g_{9} (m + 1) = - 8

lo g_{10} (x) = 3 lo g_{10} (2)

lo g_{2} (x) = - 8

lo g_{2} (x) = 36

3 ln (4 x + 5) - 19 = - 7