log_{2}(3x+10)=5

Lösung

lo g_{2} (3 x + 10) = 5

x = \frac{22}{3}

Dezimale

x = 7.33333 \dots

Schritte zur Lösung

lo g_{2} (3 x + 10) = 5

Wende die log Regel an

3 x + 10 = 32

Löse

3 x + 10 = 32 : x = \frac{22}{3}

x = \frac{22}{3}

lo g_{3} (x) = \frac{ln ( x )}{x}

1 + 2 lo g_{10} (x) = 9

lo g_{4} (x + 5) = 3

e^{2 l n (x)} = x + 6

0 = lo g_{3} (x - 4)