ln(x^2-x)=1

Lösung

ln (x^{2} - x) = 1

x = \frac{1 + 1 + 4 e}{2}, x = \frac{1 - 1 + 4 e}{2}

Dezimale

x = 2.22287 \dots, x = - 1.22287 \dots

Schritte zur Lösung

ln (x^{2} - x) = 1

Wende die log Regel an

x^{2} - x = e

Löse

x^{2} - x = e : x = \frac{1 + 1 + 4 e}{2}, x = \frac{1 - 1 + 4 e}{2}

x = \frac{1 + 1 + 4 e}{2}, x = \frac{1 - 1 + 4 e}{2}

so l v e f or x, 2 = - lo g_{10} (x)

- 1 - 5 \cdot ln (x) = 1

lo g_{2} (k + 2) - lo g_{2} (3 - k) = - 2

lo g_{2} (x) = 1 0^{6}

2 ln (x) + ln (x) = 0