log_{2}(2x-3)=4

Lösung

lo g_{2} (2 x - 3) = 4

x = \frac{19}{2}

Dezimale

x = 9.5

Schritte zur Lösung

lo g_{2} (2 x - 3) = 4

Wende die log Regel an

2 x - 3 = 16

Löse

2 x - 3 = 16 : x = \frac{19}{2}

x = \frac{19}{2}

0.76 = lo g_{10} (x)

lo g_{10} (x - 1) = 3

lo g_{2} (x - 8) = 2 - lo g_{2} (x - 5)

lo g_{2} (2 - 3 x) = 1

lo g_{x} (25) = \frac{2}{3}