ln((x+1)^2)=2

Lösung

ln ((x + 1)^{2}) = 2

x = e - 1, x = - e - 1

Dezimale

x = 1.71828 \dots, x = - 3.71828 \dots

Schritte zur Lösung

ln ((x + 1)^{2}) = 2

Wende die log Regel an

(x + 1)^{2} = e^{2}

Löse

(x + 1)^{2} = e^{2} : x = e - 1, x = - e - 1

x = e - 1, x = - e - 1

lo g_{3} (x) = - 3

3 = - lo g_{10} (x)

ln (x) - ln (x^{2}) = 5

lo g_{10} (x^{3} + 2000) = 2

lo g_{x} (49) = 2