|x^2-3x-1|=1

Lösung

x^{2} - 3 x - 1 = 1

x = \frac{3 - 17}{2} or x = 0 or x = 3 or x = \frac{3 + 17}{2}

Dezimale

x = - 0.56155 \dots, x = 0, x = 3, x = 3.56155 \dots

Schritte zur Lösung

x^{2} - 3 x - 1 = 1

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

x^{2} - 3 x - 1 = - 1 or x^{2} - 3 x - 1 = 1

x^{2} - 3 x - 1 = - 1 or x^{2} - 3 x - 1 = 1

(x = 0 or x = 3) or (x = \frac{3 - 17}{2} or x = \frac{3 + 17}{2})

x = \frac{3 - 17}{2} or x = 0 or x = 3 or x = \frac{3 + 17}{2}

5 ∣ 5 x - 7 ∣ - 1 = 14

5 - x^{2} = 3 - x

- 6 = ∣ 3 x - 3 ∣

- 3 ∣ x - 5 ∣ + 4 = 13

∣ y ∣ = 16, x + y = 0