|x^2-5x+4|=0

Lösung

x^{2} - 5 x + 4 = 0

x = 1 or x = 4

Schritte zur Lösung

x^{2} - 5 x + 4 = 0

Wende Absoluteregel an: Wenn

∣ u ∣ = 0

dann

u = 0

x^{2} - 5 x + 4 = 0

x^{2} - 5 x + 4 = 0 : x = 4, x = 1

x = 1 or x = 4

∣ d + 8 ∣ - 10 = - 9

x^{2} - 1 = ∣ x ∣

x^{2} = ∣ 5 x + 6 ∣

\frac{3}{2} x - 6 = 6

- 8 ∣ n ∣ + 7 = - 41