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人気のある代数 >

solvefor x,f=10+x^3f(27)

解

解く

x, f = 10 + x^{3} f (27)

解

x = 3 \frac{f - 10}{f ( 27 )}, x = - \frac{3 \frac{f - 10}{f ( 27 )}}{2} + \frac{3 \frac{f - 10}{f ( 27 )} 3}{2} i, x = - \frac{3 \frac{f - 10}{f ( 27 )}}{2} - \frac{3 \frac{f - 10}{f ( 27 )} 3}{2} i; f (27) \neq = 0

解答ステップ

f = 10 + x^{3} f (27)

辺を交換する

10 + x^{3} f (27) = f

10

を右側に移動します

x^{3} f (27) = f - 10

以下で両辺を割る

f (27); f (27) \neq = 0

x^{3} = \frac{f - 10}{f ( 27 )}; f (27) \neq = 0

x^{3} = f (a)

では, 解は

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

x = 3 \frac{f - 10}{f ( 27 )}, x = 3 \frac{f - 10}{f ( 27 )} \frac{- 1 + 3 i}{2}, x = 3 \frac{f - 10}{f ( 27 )} \frac{- 1 - 3 i}{2}; f (27) \neq = 0

簡素化

3 \frac{f - 10}{f ( 27 )} \frac{- 1 + 3 i}{2} : - \frac{3 \frac{f - 10}{f ( 27 )}}{2} + \frac{3 \frac{f - 10}{f ( 27 )} 3}{2} i

簡素化

3 \frac{f - 10}{f ( 27 )} \frac{- 1 - 3 i}{2} : - \frac{3 \frac{f - 10}{f ( 27 )}}{2} - \frac{3 \frac{f - 10}{f ( 27 )} 3}{2} i

x = 3 \frac{f - 10}{f ( 27 )}, x = - \frac{3 \frac{f - 10}{f ( 27 )}}{2} + \frac{3 \frac{f - 10}{f ( 27 )} 3}{2} i, x = - \frac{3 \frac{f - 10}{f ( 27 )}}{2} - \frac{3 \frac{f - 10}{f ( 27 )} 3}{2} i; f (27) \neq = 0

グラフ

人気の例

(x-2)^4(x+1)(x+4)=0

(x - 2)^{4} (x + 1) (x + 4) = 0

(3x-2)^3=(2-3x)^2

(3 x - 2)^{3} = (2 - 3 x)^{2}

solvefor x,a=(2x^5y^3)^3

so l v e f or x, a = (2 x^{5} y^{3})^{3}

a^{3} + 12 a - 6.5 = 0

76= 1/2 (h(h^2+3))

76 = \frac{1}{2} (h (h^{2} + 3))