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人気のある代数 >

25000*(1+x)^3=26765

解

25000 \cdot (1 + x)^{3} = 26765

解

x = \frac{3 5353}{10 3 5} - 1, x = \frac{5 ^{\frac{2}{3}} ( - 3 5353 - 20 3 5 )}{100} + i \frac{5 ^{\frac{2}{3}} 3 5353 3}{100}, x = \frac{5 ^{\frac{2}{3}} ( - 3 5353 - 20 3 5 )}{100} - i \frac{5 ^{\frac{2}{3}} 3 5353 3}{100}

解答ステップ

25000 (1 + x)^{3} = 26765

以下で両辺を割る

25000

(1 + x)^{3} = \frac{5353}{5000}

g^{3} (x) = f (a)

の場合, 解は

g (x) = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

解く

1 + x = 3 \frac{5353}{5000} : x = \frac{3 5353}{10 3 5} - 1

解く

1 + x = 3 \frac{5353}{5000} \frac{- 1 + 3 i}{2} : x = \frac{5 ^{\frac{2}{3}} ( - 3 5353 - 20 3 5 )}{100} + i \frac{5 ^{\frac{2}{3}} 3 5353 3}{100}

解く

1 + x = 3 \frac{5353}{5000} \frac{- 1 - 3 i}{2} : x = \frac{5 ^{\frac{2}{3}} ( - 3 5353 - 20 3 5 )}{100} - i \frac{5 ^{\frac{2}{3}} 3 5353 3}{100}

解答は

x = \frac{3 5353}{10 3 5} - 1, x = \frac{5 ^{\frac{2}{3}} ( - 3 5353 - 20 3 5 )}{100} + i \frac{5 ^{\frac{2}{3}} 3 5353 3}{100}, x = \frac{5 ^{\frac{2}{3}} ( - 3 5353 - 20 3 5 )}{100} - i \frac{5 ^{\frac{2}{3}} 3 5353 3}{100}

グラフ

人気の例

x^3(x-7)=x(x-7)

x^{3} (x - 7) = x (x - 7)

(x + 8)^{3} - 81 = 0

0 = x^{4} - 4 x^{2}

6x^4-7x^3-x^2+67x-105=0

6 x^{4} - 7 x^{3} - x^{2} + 67 x - 105 = 0

最小公倍数 x,f(x)=,(f(x)\circ g(x))5-x^3

l c m x, f (x) =, (f (x) \circ g (x)) 5 - x^{3}