7^{(3-x)}=5^{(x+1)}

Lösung

7^{(3 - x)} = 5^{(x + 1)}

x = \frac{3 ln ( 7 ) - ln ( 5 )}{ln ( 35 )}

Dezimale

x = 1.18927 \dots

Schritte zur Lösung

7^{(3 - x)} = 5^{(x + 1)}

Wende Exponentenregel an

(3 - x) ln (7) = (x + 1) ln (5)

Löse

(3 - x) ln (7) = (x + 1) ln (5) : x = \frac{3 ln ( 7 ) - ln ( 5 )}{ln ( 35 )}

x = \frac{3 ln ( 7 ) - ln ( 5 )}{ln ( 35 )}

1.0 1^{n} = 2

ln (2^{3 x + 1}) = 5

e = 1 0^{x}

3^{x - 1} = 134

6 4^{x} - 8 = 0