2^{2x-1}=16

Lösung

2^{2 x - 1} = 16

x = \frac{5}{2}

Dezimale

x = 2.5

Schritte zur Lösung

2^{2 x - 1} = 16

Wende Exponentenregel an

2 x - 1 = 4

Löse

2 x - 1 = 4 : x = \frac{5}{2}

x = \frac{5}{2}

x^{- 3 + l o g_{3} (x)} = 81

12 = 7^{x}

(5 x + 11)^{2 x - 1} = (5 x + 11)^{x - 6}

e^{3 x} = 14

so l v e f or x, f = - 2 ((- 6)^{(x + 5)})