9^{x^2+x}=27^{x^2-1}

Lösung

9^{x^{2} + x} = 2 7^{x^{2} - 1}

x = - 1, x = 3

Schritte zur Lösung

9^{x^{2} + x} = 2 7^{x^{2} - 1}

Wende Exponentenregel an

2 (x^{2} + x) = 3 (x^{2} - 1)

Löse

2 (x^{2} + x) = 3 (x^{2} - 1) : x = - 1, x = 3

x = - 1, x = 3

2 7^{x^{2} - x - 6} = 1

2 x 1 - 3^{x - 3} = 27

6 = 4^{2 X - 1}

2^{x^{2}} = 4^{2 (x - 1)}

e^{z} - e^{- z} = 0