2^{3x}=4^{2x-1}

Lösung

2^{3 x} = 4^{2 x - 1}

x = 2

Schritte zur Lösung

2^{3 x} = 4^{2 x - 1}

Wende Exponentenregel an

3 x = 2 (2 x - 1)

Löse

3 x = 2 (2 x - 1) : x = 2

x = 2

e^{7 x} = 17

lo g_{10} (x^{l o g_{10} (x)}) = 1

e^{7 x} = 10

3^{x} = \frac{1}{5}

3^{x} = \frac{1}{8}