4^{3x-1}=9^{x+2}

Lösung

4^{3 x - 1} = 9^{x + 2}

x = \frac{ln ( 18 )}{3 ln ( 2 ) - ln ( 3 )}

Dezimale

x = 2.94686 \dots

Schritte zur Lösung

4^{3 x - 1} = 9^{x + 2}

Wende Exponentenregel an

(3 x - 1) ln (4) = (x + 2) ln (9)

Löse

(3 x - 1) ln (4) = (x + 2) ln (9) : x = \frac{ln ( 18 )}{3 ln ( 2 ) - ln ( 3 )}

x = \frac{ln ( 18 )}{3 ln ( 2 ) - ln ( 3 )}

16 (4^{2 x}) + 79 (4^{x}) - 5 = 0

e^{x + 2} = 2

8^{x - 1} = 125

(\frac{1}{7})^{x} = \frac{1}{49}

51 = 4 e^{3 x}